Solve for x 4x+x-3-9+4x=6

$4 x + x - 3 - 9 + 4 x = 6$

Simplify $4 x + x - 3 - 9 + 4 x$ .

Add $4 x$ and $x$ .

$5 x - 3 - 9 + 4 x = 6$

Add $5 x$ and $4 x$ .

$9 x - 3 - 9 = 6$

Subtract $9$ from $- 3$ .

$9 x - 12 = 6$

Move all terms not containing $x$ to the right side of the equation.

Add $12$ to both sides of the equation.

$9 x = 6 + 12$

Add $6$ and $12$ .

$9 x = 18$

Divide each term in $9 x = 18$ by $9$ and simplify.

Divide each term in $9 x = 18$ by $9$ .

$\frac{9 x}{9} = \frac{18}{9}$

Simplify the left side.

Cancel the common factor of $9$ .

Cancel the common factor.

$\frac{9 x}{9} = \frac{18}{9}$

Divide $x$ by $1$ .

$x = \frac{18}{9}$

Simplify the right side.

Divide $18$ by $9$ .

$x = 2$