Solve for x 5(1+4x)-5=80

$5 (1 + 4 x) - 5 = 80$

Step 1

Simplify $5 (1 + 4 x) - 5$ .

Simplify each term.

Apply the distributive property.

$5 \cdot 1 + 5 (4 x) - 5 = 80$

Multiply $5$ by $1$ .

$5 + 5 (4 x) - 5 = 80$

Multiply $4$ by $5$ .

$5 + 20 x - 5 = 80$

Combine the opposite terms in $5 + 20 x - 5$ .

Subtract $5$ from $5$ .

$20 x + 0 = 80$

Add $20 x$ and $0$ .

$20 x = 80$

Step 2

Divide each term in $20 x = 80$ by $20$ and simplify.

Divide each term in $20 x = 80$ by $20$ .

$\frac{20 x}{20} = \frac{80}{20}$

Simplify the left side.

Cancel the common factor of $20$ .

Cancel the common factor.

$\frac{20 x}{20} = \frac{80}{20}$

Divide $x$ by $1$ .

$x = \frac{80}{20}$

Simplify the right side.

Divide $80$ by $20$ .

$x = 4$