Solve for x -5(1-5x)+5(-8x-2)=-4x-8x

$- 5 (1 - 5 x) + 5 (- 8 x - 2) = - 4 x - 8 x$

Step 1

Simplify $- 5 (1 - 5 x) + 5 (- 8 x - 2)$ .

Simplify each term.

Apply the distributive property.

$- 5 \cdot 1 - 5 (- 5 x) + 5 (- 8 x - 2) = - 4 x - 8 x$

Multiply $- 5$ by $1$ .

$- 5 - 5 (- 5 x) + 5 (- 8 x - 2) = - 4 x - 8 x$

Multiply $- 5$ by $- 5$ .

$- 5 + 25 x + 5 (- 8 x - 2) = - 4 x - 8 x$

Apply the distributive property.

$- 5 + 25 x + 5 (- 8 x) + 5 \cdot - 2 = - 4 x - 8 x$

Multiply $- 8$ by $5$ .

$- 5 + 25 x - 40 x + 5 \cdot - 2 = - 4 x - 8 x$

Multiply $5$ by $- 2$ .

$- 5 + 25 x - 40 x - 10 = - 4 x - 8 x$

Simplify by adding terms.

Subtract $10$ from $- 5$ .

$25 x - 40 x - 15 = - 4 x - 8 x$

Subtract $40 x$ from $25 x$ .

$- 15 x - 15 = - 4 x - 8 x$

Step 2

Subtract $8 x$ from $- 4 x$ .

$- 15 x - 15 = - 12 x$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $12 x$ to both sides of the equation.

$- 15 x - 15 + 12 x = 0$

Add $- 15 x$ and $12 x$ .

$- 3 x - 15 = 0$

Step 4

Add $15$ to both sides of the equation.

$- 3 x = 15$

Step 5

Divide each term in $- 3 x = 15$ by $- 3$ and simplify.

Divide each term in $- 3 x = 15$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{15}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{15}{- 3}$

Divide $x$ by $1$ .

$x = \frac{15}{- 3}$

Simplify the right side.

Divide $15$ by $- 3$ .

$x = - 5$

Solve for x -5(1-5x)+5(-8x-2)=-4x-8x

Related Questions

Support LCMGCF.com by disabling your adblocker.