Solve for x 5(2x-1)=-5+10x

$5 (2 x - 1) = - 5 + 10 x$

Step 1

Simplify $5 (2 x - 1)$ .

Rewrite.

$0 + 0 + 5 (2 x - 1) = - 5 + 10 x$

Simplify by adding zeros.

$5 (2 x - 1) = - 5 + 10 x$

Apply the distributive property.

$5 (2 x) + 5 \cdot - 1 = - 5 + 10 x$

Multiply.

Multiply $2$ by $5$ .

$10 x + 5 \cdot - 1 = - 5 + 10 x$

Multiply $5$ by $- 1$ .

$10 x - 5 = - 5 + 10 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $10 x$ from both sides of the equation.

$10 x - 5 - 10 x = - 5$

Combine the opposite terms in $10 x - 5 - 10 x$ .

Subtract $10 x$ from $10 x$ .

$0 - 5 = - 5$

Subtract $5$ from $0$ .

$- 5 = - 5$

Step 3

Since $- 5 = - 5$ , the equation will always be true for any value of $x$ .

All real numbers

Step 4

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$