Solve for x 5-3(1/2x+2)=-7

$5 - 3 (\frac{1}{2} x + 2) = - 7$

Simplify $5 - 3 (\frac{1}{2} x + 2)$ .

Simplify each term.

Combine $\frac{1}{2}$ and $x$ .

$5 - 3 (\frac{x}{2} + 2) = - 7$

Apply the distributive property.

$5 - 3 \frac{x}{2} - 3 \cdot 2 = - 7$

Combine $- 3$ and $\frac{x}{2}$ .

$5 + \frac{- 3 x}{2} - 3 \cdot 2 = - 7$

Multiply $- 3$ by $2$ .

$5 + \frac{- 3 x}{2} - 6 = - 7$

Move the negative in front of the fraction.

$5 - \frac{3 x}{2} - 6 = - 7$

Subtract $6$ from $5$ .

$- \frac{3 x}{2} - 1 = - 7$

Move all terms not containing $x$ to the right side of the equation.

Add $1$ to both sides of the equation.

$- \frac{3 x}{2} = - 7 + 1$

Add $- 7$ and $1$ .

$- \frac{3 x}{2} = - 6$

Multiply both sides of the equation by $- \frac{2}{3}$ .

$- \frac{2}{3} (- \frac{3 x}{2}) = - \frac{2}{3} \cdot - 6$

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{2}{3} (- \frac{3 x}{2})$ .

Cancel the common factor of $2$ .

Move the leading negative in $- \frac{2}{3}$ into the numerator.

$\frac{- 2}{3} (- \frac{3 x}{2}) = - \frac{2}{3} \cdot - 6$

Move the leading negative in $- \frac{3 x}{2}$ into the numerator.

$\frac{- 2}{3} \cdot \frac{- 3 x}{2} = - \frac{2}{3} \cdot - 6$

Factor $2$ out of $- 2$ .

$\frac{2 (- 1)}{3} \cdot \frac{- 3 x}{2} = - \frac{2}{3} \cdot - 6$

Cancel the common factor.

$\frac{2 \cdot - 1}{3} \cdot \frac{- 3 x}{2} = - \frac{2}{3} \cdot - 6$

Rewrite the expression.

$\frac{- 1}{3} (- 3 x) = - \frac{2}{3} \cdot - 6$

Cancel the common factor of $3$ .

Factor $3$ out of $- 3 x$ .

$\frac{- 1}{3} (3 (- x)) = - \frac{2}{3} \cdot - 6$

Cancel the common factor.

$\frac{- 1}{3} (3 (- x)) = - \frac{2}{3} \cdot - 6$

Rewrite the expression.

$- - x = - \frac{2}{3} \cdot - 6$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{2}{3} \cdot - 6$

Multiply $x$ by $1$ .

$x = - \frac{2}{3} \cdot - 6$

Simplify the right side.

Simplify $- \frac{2}{3} \cdot - 6$ .

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{2}{3}$ into the numerator.

$x = \frac{- 2}{3} \cdot - 6$

Factor $3$ out of $- 6$ .

$x = \frac{- 2}{3} \cdot (3 (- 2))$

Cancel the common factor.

$x = \frac{- 2}{3} \cdot (3 \cdot - 2)$

Rewrite the expression.

$x = - 2 \cdot - 2$

Multiply $- 2$ by $- 2$ .

$x = 4$

Solve for x 5-3(1/2x+2)=-7

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