Solve for x -5/3x=-10

$- \frac{5}{3} x = - 10$

Step 1

Multiply both sides of the equation by $- \frac{3}{5}$ .

$- \frac{3}{5} (- \frac{5}{3} x) = - \frac{3}{5} \cdot - 10$

Step 2

Simplify both sides of the equation.

Simplify the left side.

Simplify $- \frac{3}{5} (- \frac{5}{3} x)$ .

Combine $x$ and $\frac{5}{3}$ .

$- \frac{3}{5} (- \frac{x \cdot 5}{3}) = - \frac{3}{5} \cdot - 10$

Cancel the common factor of $3$ .

Move the leading negative in $- \frac{3}{5}$ into the numerator.

$\frac{- 3}{5} (- \frac{x \cdot 5}{3}) = - \frac{3}{5} \cdot - 10$

Move the leading negative in $- \frac{x \cdot 5}{3}$ into the numerator.

$\frac{- 3}{5} \cdot \frac{- x \cdot 5}{3} = - \frac{3}{5} \cdot - 10$

Factor $3$ out of $- 3$ .

$\frac{3 (- 1)}{5} \cdot \frac{- x \cdot 5}{3} = - \frac{3}{5} \cdot - 10$

Cancel the common factor.

$\frac{3 \cdot - 1}{5} \cdot \frac{- x \cdot 5}{3} = - \frac{3}{5} \cdot - 10$

Rewrite the expression.

$\frac{- 1}{5} (- x \cdot 5) = - \frac{3}{5} \cdot - 10$

Cancel the common factor of $5$ .

Factor $5$ out of $- x \cdot 5$ .

$\frac{- 1}{5} (5 \cdot (- x)) = - \frac{3}{5} \cdot - 10$

Cancel the common factor.

$\frac{- 1}{5} (5 \cdot (- x)) = - \frac{3}{5} \cdot - 10$

Rewrite the expression.

$- - x = - \frac{3}{5} \cdot - 10$

Multiply.

Multiply $- 1$ by $- 1$ .

$1 x = - \frac{3}{5} \cdot - 10$

Multiply $x$ by $1$ .

$x = - \frac{3}{5} \cdot - 10$

Simplify the right side.

Simplify $- \frac{3}{5} \cdot - 10$ .

Cancel the common factor of $5$ .

Move the leading negative in $- \frac{3}{5}$ into the numerator.

$x = \frac{- 3}{5} \cdot - 10$

Factor $5$ out of $- 10$ .

$x = \frac{- 3}{5} \cdot (5 (- 2))$

Cancel the common factor.

$x = \frac{- 3}{5} \cdot (5 \cdot - 2)$

Rewrite the expression.

$x = - 3 \cdot - 2$

Multiply $- 3$ by $- 2$ .

$x = 6$

Solve for x -5/3x=-10

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