Solve for x -(5/4x+1)+1/4=1

$- (\frac{5}{4} x + 1) + \frac{1}{4} = 1$

Simplify $- (\frac{5}{4} x + 1) + \frac{1}{4}$ .

Simplify each term.

Combine $\frac{5}{4}$ and $x$ .

$- (\frac{5 x}{4} + 1) + \frac{1}{4} = 1$

Apply the distributive property.

$- \frac{5 x}{4} - 1 \cdot 1 + \frac{1}{4} = 1$

Multiply $- 1$ by $1$ .

$- \frac{5 x}{4} - 1 + \frac{1}{4} = 1$

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- \frac{5 x}{4} - 1 \cdot \frac{4}{4} + \frac{1}{4} = 1$

Combine $- 1$ and $\frac{4}{4}$ .

$- \frac{5 x}{4} + \frac{- 1 \cdot 4}{4} + \frac{1}{4} = 1$

Combine the numerators over the common denominator.

$- \frac{5 x}{4} + \frac{- 1 \cdot 4 + 1}{4} = 1$

Simplify the numerator.

Multiply $- 1$ by $4$ .

$- \frac{5 x}{4} + \frac{- 4 + 1}{4} = 1$

Add $- 4$ and $1$ .

$- \frac{5 x}{4} + \frac{- 3}{4} = 1$

Move the negative in front of the fraction.

$- \frac{5 x}{4} - \frac{3}{4} = 1$

Move all terms not containing $x$ to the right side of the equation.

Add $\frac{3}{4}$ to both sides of the equation.

$- \frac{5 x}{4} = 1 + \frac{3}{4}$

Write $1$ as a fraction with a common denominator.

$- \frac{5 x}{4} = \frac{4}{4} + \frac{3}{4}$

Combine the numerators over the common denominator.

$- \frac{5 x}{4} = \frac{4 + 3}{4}$

Add $4$ and $3$ .

$- \frac{5 x}{4} = \frac{7}{4}$

Since the expression on each side of the equation has the same denominator, the numerators must be equal.

$- 5 x = 7$

Divide each term in $- 5 x = 7$ by $- 5$ and simplify.

Divide each term in $- 5 x = 7$ by $- 5$ .

$\frac{- 5 x}{- 5} = \frac{7}{- 5}$

Simplify the left side.

Cancel the common factor of $- 5$ .

Cancel the common factor.

$\frac{- 5 x}{- 5} = \frac{7}{- 5}$

Divide $x$ by $1$ .

$x = \frac{7}{- 5}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{7}{5}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{7}{5}$

Decimal Form:

$x = - 1.4$

Mixed Number Form:

$x = - 1 \frac{2}{5}$

Solve for x -(5/4x+1)+1/4=1

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