Solve for x -5(4x-5)=21(7-x)

$- 5 (4 x - 5) = 21 (7 - x)$

Simplify $- 5 (4 x - 5)$ .

Start simplifying.

$0 + 0 - 5 (4 x - 5) = 21 (7 - x)$

Simplify by adding zeros.

$- 5 (4 x - 5) = 21 (7 - x)$

Apply the distributive property.

$- 5 (4 x) - 5 \cdot - 5 = 21 (7 - x)$

Multiply.

Multiply $4$ by $- 5$ .

$- 20 x - 5 \cdot - 5 = 21 (7 - x)$

Multiply $- 5$ by $- 5$ .

$- 20 x + 25 = 21 (7 - x)$

Simplify $21 (7 - x)$ .

Apply the distributive property.

$- 20 x + 25 = 21 \cdot 7 + 21 (- x)$

Multiply.

Multiply $21$ by $7$ .

$- 20 x + 25 = 147 + 21 (- x)$

Multiply $- 1$ by $21$ .

$- 20 x + 25 = 147 - 21 x$

Move all terms containing $x$ to the left side of the equation.

Add $21 x$ to both sides of the equation.

$- 20 x + 25 + 21 x = 147$

Add $- 20 x$ and $21 x$ .

$x + 25 = 147$

Move all terms not containing $x$ to the right side of the equation.

Subtract $25$ from both sides of the equation.

$x = 147 - 25$

Subtract $25$ from $147$ .

$x = 122$