Solve for x 5+5(x+4)<=20

$5 + 5 (x + 4) \leq 20$

Step 1

Simplify $5 + 5 (x + 4)$ .

Simplify each term.

Apply the distributive property.

$5 + 5 x + 5 \cdot 4 \leq 20$

Multiply $5$ by $4$ .

$5 + 5 x + 20 \leq 20$

Add $5$ and $20$ .

$5 x + 25 \leq 20$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $25$ from both sides of the inequality.

$5 x \leq 20 - 25$

Subtract $25$ from $20$ .

$5 x \leq - 5$

Step 3

Divide each term in $5 x \leq - 5$ by $5$ and simplify.

Divide each term in $5 x \leq - 5$ by $5$ .

$\frac{5 x}{5} \leq \frac{- 5}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} \leq \frac{- 5}{5}$

Divide $x$ by $1$ .

$x \leq \frac{- 5}{5}$

Simplify the right side.

Divide $- 5$ by $5$ .

$x \leq - 1$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \leq - 1$

Interval Notation:

$(- \infty, - 1]$