Solve for x 5/8x-1>=9

$\frac{5}{8} x - 1 \geq 9$

Combine $\frac{5}{8}$ and $x$ .

$\frac{5 x}{8} - 1 \geq 9$

Move all terms not containing $x$ to the right side of the inequality.

Add $1$ to both sides of the inequality.

$\frac{5 x}{8} \geq 9 + 1$

Add $9$ and $1$ .

$\frac{5 x}{8} \geq 10$

Multiply both sides by $8$ .

$\frac{5 x}{8} \cdot 8 \geq 10 \cdot 8$

Simplify.

Simplify the left side.

Cancel the common factor of $8$ .

Cancel the common factor.

$\frac{5 x}{8} \cdot 8 \geq 10 \cdot 8$

Rewrite the expression.

$5 x \geq 10 \cdot 8$

Simplify the right side.

Multiply $10$ by $8$ .

$5 x \geq 80$

Divide each term in $5 x \geq 80$ by $5$ and simplify.

Divide each term in $5 x \geq 80$ by $5$ .

$\frac{5 x}{5} \geq \frac{80}{5}$

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} \geq \frac{80}{5}$

Divide $x$ by $1$ .

$x \geq \frac{80}{5}$

Simplify the right side.

Divide $80$ by $5$ .

$x \geq 16$

The result can be shown in multiple forms.

Inequality Form:

$x \geq 16$

Interval Notation:

$[16, \infty)$