Solve for x 5+(8x)/7=29

$5 + \frac{8 x}{7} = 29$

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$\frac{8 x}{7} = 29 - 5$

Subtract $5$ from $29$ .

$\frac{8 x}{7} = 24$

Multiply both sides of the equation by $\frac{7}{8}$ .

$\frac{7}{8} \cdot \frac{8 x}{7} = \frac{7}{8} \cdot 24$

Simplify both sides of the equation.

Simplify the left side.

Simplify $\frac{7}{8} \cdot \frac{8 x}{7}$ .

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7}{8} \cdot \frac{8 x}{7} = \frac{7}{8} \cdot 24$

Rewrite the expression.

$\frac{1}{8} (8 x) = \frac{7}{8} \cdot 24$

Cancel the common factor of $8$ .

Factor $8$ out of $8 x$ .

$\frac{1}{8} (8 (x)) = \frac{7}{8} \cdot 24$

Cancel the common factor.

$\frac{1}{8} (8 x) = \frac{7}{8} \cdot 24$

Rewrite the expression.

$x = \frac{7}{8} \cdot 24$

Simplify the right side.

Simplify $\frac{7}{8} \cdot 24$ .

Cancel the common factor of $8$ .

Factor $8$ out of $24$ .

$x = \frac{7}{8} \cdot (8 (3))$

Cancel the common factor.

$x = \frac{7}{8} \cdot (8 \cdot 3)$

Rewrite the expression.

$x = 7 \cdot 3$

Multiply $7$ by $3$ .

$x = 21$