Solve for x 5^(x+1)=25

$5^{x + 1} = 25$

Step 1

Create equivalent expressions in the equation that all have equal bases.

$5^{x + 1} = 5^{2}$

Step 2

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x + 1 = 2$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$x = 2 - 1$

Subtract $1$ from $2$ .

$x = 1$