Solve for x 5(x+1)=3-2(5x+4)

$5 (x + 1) = 3 - 2 (5 x + 4)$

Step 1

Simplify $5 (x + 1)$ .

Rewrite.

$0 + 0 + 5 (x + 1) = 3 - 2 (5 x + 4)$

Simplify by adding zeros.

$5 (x + 1) = 3 - 2 (5 x + 4)$

Apply the distributive property.

$5 x + 5 \cdot 1 = 3 - 2 (5 x + 4)$

Multiply $5$ by $1$ .

$5 x + 5 = 3 - 2 (5 x + 4)$

Step 2

Simplify $3 - 2 (5 x + 4)$ .

Simplify each term.

Apply the distributive property.

$5 x + 5 = 3 - 2 (5 x) - 2 \cdot 4$

Multiply $5$ by $- 2$ .

$5 x + 5 = 3 - 10 x - 2 \cdot 4$

Multiply $- 2$ by $4$ .

$5 x + 5 = 3 - 10 x - 8$

Subtract $8$ from $3$ .

$5 x + 5 = - 10 x - 5$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $10 x$ to both sides of the equation.

$5 x + 5 + 10 x = - 5$

Add $5 x$ and $10 x$ .

$15 x + 5 = - 5$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$15 x = - 5 - 5$

Subtract $5$ from $- 5$ .

$15 x = - 10$

Step 5

Divide each term in $15 x = - 10$ by $15$ and simplify.

Divide each term in $15 x = - 10$ by $15$ .

$\frac{15 x}{15} = \frac{- 10}{15}$

Simplify the left side.

Cancel the common factor of $15$ .

Cancel the common factor.

$\frac{15 x}{15} = \frac{- 10}{15}$

Divide $x$ by $1$ .

$x = \frac{- 10}{15}$

Simplify the right side.

Cancel the common factor of $- 10$ and $15$ .

Factor $5$ out of $- 10$ .

$x = \frac{5 (- 2)}{15}$

Cancel the common factors.

Factor $5$ out of $15$ .

$x = \frac{5 \cdot - 2}{5 \cdot 3}$

Cancel the common factor.

$x = \frac{5 \cdot - 2}{5 \cdot 3}$

Rewrite the expression.

$x = \frac{- 2}{3}$

Move the negative in front of the fraction.

$x = - \frac{2}{3}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{2}{3}$

Decimal Form:

$x = - 0.\overline{6}$

Solve for x 5(x+1)=3-2(5x+4)

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