Solve for x 5(x+1)=4(x+8)

$5 (x + 1) = 4 (x + 8)$

Step 1

Simplify $5 (x + 1)$ .

Rewrite.

$0 + 0 + 5 (x + 1) = 4 (x + 8)$

Simplify by adding zeros.

$5 (x + 1) = 4 (x + 8)$

Apply the distributive property.

$5 x + 5 \cdot 1 = 4 (x + 8)$

Multiply $5$ by $1$ .

$5 x + 5 = 4 (x + 8)$

Step 2

Simplify $4 (x + 8)$ .

Apply the distributive property.

$5 x + 5 = 4 x + 4 \cdot 8$

Multiply $4$ by $8$ .

$5 x + 5 = 4 x + 32$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$5 x + 5 - 4 x = 32$

Subtract $4 x$ from $5 x$ .

$x + 5 = 32$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$x = 32 - 5$

Subtract $5$ from $32$ .

$x = 27$