Solve for x 5^(x+3)>=25

$5^{x + 3} \geq 25$

Create equivalent expressions in the equation that all have equal bases.

$5^{x + 3} \geq 5^{2}$

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$x + 3 \geq 2$

Move all terms not containing $x$ to the right side of the inequality.

Subtract $3$ from both sides of the inequality.

$x \geq 2 - 3$

Subtract $3$ from $2$ .

$x \geq - 1$

The result can be shown in multiple forms.

Inequality Form:

$x \geq - 1$

Interval Notation:

$[- 1, \infty)$