Solve for x 5(x-3)+4(x+3)=3(x-1)

$5 (x - 3) + 4 (x + 3) = 3 (x - 1)$

Step 1

Simplify $5 (x - 3) + 4 (x + 3)$ .

Simplify each term.

Apply the distributive property.

$5 x + 5 \cdot - 3 + 4 (x + 3) = 3 (x - 1)$

Multiply $5$ by $- 3$ .

$5 x - 15 + 4 (x + 3) = 3 (x - 1)$

Apply the distributive property.

$5 x - 15 + 4 x + 4 \cdot 3 = 3 (x - 1)$

Multiply $4$ by $3$ .

$5 x - 15 + 4 x + 12 = 3 (x - 1)$

Simplify by adding terms.

Add $5 x$ and $4 x$ .

$9 x - 15 + 12 = 3 (x - 1)$

Add $- 15$ and $12$ .

$9 x - 3 = 3 (x - 1)$

Step 2

Simplify $3 (x - 1)$ .

Apply the distributive property.

$9 x - 3 = 3 x + 3 \cdot - 1$

Multiply $3$ by $- 1$ .

$9 x - 3 = 3 x - 3$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$9 x - 3 - 3 x = - 3$

Subtract $3 x$ from $9 x$ .

$6 x - 3 = - 3$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$6 x = - 3 + 3$

Add $- 3$ and $3$ .

$6 x = 0$

Step 5

Divide each term in $6 x = 0$ by $6$ and simplify.

Divide each term in $6 x = 0$ by $6$ .

$\frac{6 x}{6} = \frac{0}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x}{6} = \frac{0}{6}$

Divide $x$ by $1$ .

$x = \frac{0}{6}$

Simplify the right side.

Divide $0$ by $6$ .

$x = 0$

Solve for x 5(x-3)+4(x+3)=3(x-1)

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