Solve for x 5(x+3)+4x-3=-(2x-4)+2

$5 (x + 3) + 4 x - 3 = - (2 x - 4) + 2$

Step 1

Simplify $5 (x + 3) + 4 x - 3$ .

Simplify each term.

Apply the distributive property.

$5 x + 5 \cdot 3 + 4 x - 3 = - (2 x - 4) + 2$

Multiply $5$ by $3$ .

$5 x + 15 + 4 x - 3 = - (2 x - 4) + 2$

Simplify by adding terms.

Add $5 x$ and $4 x$ .

$9 x + 15 - 3 = - (2 x - 4) + 2$

Subtract $3$ from $15$ .

$9 x + 12 = - (2 x - 4) + 2$

Step 2

Simplify $- (2 x - 4) + 2$ .

Simplify each term.

Apply the distributive property.

$9 x + 12 = - (2 x) - - 4 + 2$

Multiply $2$ by $- 1$ .

$9 x + 12 = - 2 x - - 4 + 2$

Multiply $- 1$ by $- 4$ .

$9 x + 12 = - 2 x + 4 + 2$

Add $4$ and $2$ .

$9 x + 12 = - 2 x + 6$

Step 3

Move all terms containing $x$ to the left side of the equation.

Add $2 x$ to both sides of the equation.

$9 x + 12 + 2 x = 6$

Add $9 x$ and $2 x$ .

$11 x + 12 = 6$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$11 x = 6 - 12$

Subtract $12$ from $6$ .

$11 x = - 6$

Step 5

Divide each term in $11 x = - 6$ by $11$ and simplify.

Divide each term in $11 x = - 6$ by $11$ .

$\frac{11 x}{11} = \frac{- 6}{11}$

Simplify the left side.

Cancel the common factor of $11$ .

Cancel the common factor.

$\frac{11 x}{11} = \frac{- 6}{11}$

Divide $x$ by $1$ .

$x = \frac{- 6}{11}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{6}{11}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{6}{11}$

Decimal Form:

$x = - 0.\overline{54}$

Solve for x 5(x+3)+4x-3=-(2x-4)+2

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