Solve for x 5x+2>3x+10

$5 x + 2 > 3 x + 10$

Step 1

Move all terms containing $x$ to the left side of the inequality.

Subtract $3 x$ from both sides of the inequality.

$5 x + 2 - 3 x > 10$

Subtract $3 x$ from $5 x$ .

$2 x + 2 > 10$

Step 2

Move all terms not containing $x$ to the right side of the inequality.

Subtract $2$ from both sides of the inequality.

$2 x > 10 - 2$

Subtract $2$ from $10$ .

$2 x > 8$

Step 3

Divide each term in $2 x > 8$ by $2$ and simplify.

Divide each term in $2 x > 8$ by $2$ .

$\frac{2 x}{2} > \frac{8}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} > \frac{8}{2}$

Divide $x$ by $1$ .

$x > \frac{8}{2}$

Simplify the right side.

Divide $8$ by $2$ .

$x > 4$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x > 4$

Interval Notation:

$(4, \infty)$