Solve for x 5x-2(7x+1)=14x

$5 x - 2 (7 x + 1) = 14 x$

Step 1

Simplify $5 x - 2 (7 x + 1)$ .

Simplify each term.

Apply the distributive property.

$5 x - 2 (7 x) - 2 \cdot 1 = 14 x$

Multiply $7$ by $- 2$ .

$5 x - 14 x - 2 \cdot 1 = 14 x$

Multiply $- 2$ by $1$ .

$5 x - 14 x - 2 = 14 x$

Subtract $14 x$ from $5 x$ .

$- 9 x - 2 = 14 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $14 x$ from both sides of the equation.

$- 9 x - 2 - 14 x = 0$

Subtract $14 x$ from $- 9 x$ .

$- 23 x - 2 = 0$

Step 3

Add $2$ to both sides of the equation.

$- 23 x = 2$

Step 4

Divide each term in $- 23 x = 2$ by $- 23$ and simplify.

Divide each term in $- 23 x = 2$ by $- 23$ .

$\frac{- 23 x}{- 23} = \frac{2}{- 23}$

Simplify the left side.

Cancel the common factor of $- 23$ .

Cancel the common factor.

$\frac{- 23 x}{- 23} = \frac{2}{- 23}$

Divide $x$ by $1$ .

$x = \frac{2}{- 23}$

Simplify the right side.

Move the negative in front of the fraction.

$x = - \frac{2}{23}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{2}{23}$

Decimal Form:

$x = - 0.08695652 \dots$