Solve for x 5x+3=6x-2

$5 x + 3 = 6 x - 2$

Step 1

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$5 x + 3 - 6 x = - 2$

Subtract $6 x$ from $5 x$ .

$- x + 3 = - 2$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $3$ from both sides of the equation.

$- x = - 2 - 3$

Subtract $3$ from $- 2$ .

$- x = - 5$

Step 3

Divide each term in $- x = - 5$ by $- 1$ and simplify.

Divide each term in $- x = - 5$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 5}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 5}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 5}{- 1}$

Simplify the right side.

Divide $- 5$ by $- 1$ .

$x = 5$