Solve for x 5x<=45

$5 x \leq 45$

Step 1

Divide each term in $5 x \leq 45$ by $5$ .

$\frac{5 x}{5} \leq \frac{45}{5}$

Step 2

Simplify the left side.

Cancel the common factor of $5$ .

Cancel the common factor.

$\frac{5 x}{5} \leq \frac{45}{5}$

Divide $x$ by $1$ .

$x \leq \frac{45}{5}$

$x \leq \frac{45}{5}$

$x \leq \frac{45}{5}$

Step 3

Simplify the right side.

Divide $45$ by $5$ .

$x \leq 9$

$x \leq 9$

Step 4

The result can be shown in multiple forms.

Inequality Form:

$x \leq 9$

Interval Notation:

$(- \infty, 9]$

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