Solve for x 6(2x-1)-(x-4)=-2(3x+1)

$6 (2 x - 1) - (x - 4) = - 2 (3 x + 1)$

Simplify $6 (2 x - 1) - (x - 4)$ .

Simplify each term.

Apply the distributive property.

$6 (2 x) + 6 \cdot - 1 - (x - 4) = - 2 (3 x + 1)$

Multiply $2$ by $6$ .

$12 x + 6 \cdot - 1 - (x - 4) = - 2 (3 x + 1)$

Multiply $6$ by $- 1$ .

$12 x - 6 - (x - 4) = - 2 (3 x + 1)$

Apply the distributive property.

$12 x - 6 - x - - 4 = - 2 (3 x + 1)$

Multiply $- 1$ by $- 4$ .

$12 x - 6 - x + 4 = - 2 (3 x + 1)$

Simplify by adding terms.

Subtract $x$ from $12 x$ .

$11 x - 6 + 4 = - 2 (3 x + 1)$

Add $- 6$ and $4$ .

$11 x - 2 = - 2 (3 x + 1)$

Simplify $- 2 (3 x + 1)$ .

Apply the distributive property.

$11 x - 2 = - 2 (3 x) - 2 \cdot 1$

Multiply.

Multiply $3$ by $- 2$ .

$11 x - 2 = - 6 x - 2 \cdot 1$

Multiply $- 2$ by $1$ .

$11 x - 2 = - 6 x - 2$

Move all terms containing $x$ to the left side of the equation.

Add $6 x$ to both sides of the equation.

$11 x - 2 + 6 x = - 2$

Add $11 x$ and $6 x$ .

$17 x - 2 = - 2$

Move all terms not containing $x$ to the right side of the equation.

Add $2$ to both sides of the equation.

$17 x = - 2 + 2$

Add $- 2$ and $2$ .

$17 x = 0$

Divide each term in $17 x = 0$ by $17$ and simplify.

Divide each term in $17 x = 0$ by $17$ .

$\frac{17 x}{17} = \frac{0}{17}$

Simplify the left side.

Cancel the common factor of $17$ .

Cancel the common factor.

$\frac{17 x}{17} = \frac{0}{17}$

Divide $x$ by $1$ .

$x = \frac{0}{17}$

Simplify the right side.

Divide $0$ by $17$ .

$x = 0$

Solve for x 6(2x-1)-(x-4)=-2(3x+1)

Related Questions

Support LCMGCF.com by disabling your adblocker.