Solve for x 6=-3(x+2)

$6 = - 3 (x + 2)$

Step 1

Rewrite the equation as $- 3 (x + 2) = 6$ .

$- 3 (x + 2) = 6$

Step 2

Divide each term in $- 3 (x + 2) = 6$ by $- 3$ and simplify.

Divide each term in $- 3 (x + 2) = 6$ by $- 3$ .

$\frac{- 3 (x + 2)}{- 3} = \frac{6}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 (x + 2)}{- 3} = \frac{6}{- 3}$

Divide $x + 2$ by $1$ .

$x + 2 = \frac{6}{- 3}$

Simplify the right side.

Divide $6$ by $- 3$ .

$x + 2 = - 2$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$x = - 2 - 2$

Subtract $2$ from $- 2$ .

$x = - 4$