Solve for x 6(4x+5)=3(x+8)+3

$6 (4 x + 5) = 3 (x + 8) + 3$

Step 1

Simplify $6 (4 x + 5)$ .

Rewrite.

$0 + 0 + 6 (4 x + 5) = 3 (x + 8) + 3$

Simplify by adding zeros.

$6 (4 x + 5) = 3 (x + 8) + 3$

Apply the distributive property.

$6 (4 x) + 6 \cdot 5 = 3 (x + 8) + 3$

Multiply.

Multiply $4$ by $6$ .

$24 x + 6 \cdot 5 = 3 (x + 8) + 3$

Multiply $6$ by $5$ .

$24 x + 30 = 3 (x + 8) + 3$

Step 2

Simplify $3 (x + 8) + 3$ .

Simplify each term.

Apply the distributive property.

$24 x + 30 = 3 x + 3 \cdot 8 + 3$

Multiply $3$ by $8$ .

$24 x + 30 = 3 x + 24 + 3$

Add $24$ and $3$ .

$24 x + 30 = 3 x + 27$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$24 x + 30 - 3 x = 27$

Subtract $3 x$ from $24 x$ .

$21 x + 30 = 27$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $30$ from both sides of the equation.

$21 x = 27 - 30$

Subtract $30$ from $27$ .

$21 x = - 3$

Step 5

Divide each term in $21 x = - 3$ by $21$ and simplify.

Divide each term in $21 x = - 3$ by $21$ .

$\frac{21 x}{21} = \frac{- 3}{21}$

Simplify the left side.

Cancel the common factor of $21$ .

Cancel the common factor.

$\frac{21 x}{21} = \frac{- 3}{21}$

Divide $x$ by $1$ .

$x = \frac{- 3}{21}$

Simplify the right side.

Cancel the common factor of $- 3$ and $21$ .

Factor $3$ out of $- 3$ .

$x = \frac{3 (- 1)}{21}$

Cancel the common factors.

Factor $3$ out of $21$ .

$x = \frac{3 \cdot - 1}{3 \cdot 7}$

Cancel the common factor.

$x = \frac{3 \cdot - 1}{3 \cdot 7}$

Rewrite the expression.

$x = \frac{- 1}{7}$

Move the negative in front of the fraction.

$x = - \frac{1}{7}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{1}{7}$

Decimal Form:

$x = - 0.\overline{142857}$

Solve for x 6(4x+5)=3(x+8)+3

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