Solve for x 6+8(x-1)=2(3x+4)

$6 + 8 (x - 1) = 2 (3 x + 4)$

Step 1

Simplify $6 + 8 (x - 1)$ .

Simplify each term.

Apply the distributive property.

$6 + 8 x + 8 \cdot - 1 = 2 (3 x + 4)$

Multiply $8$ by $- 1$ .

$6 + 8 x - 8 = 2 (3 x + 4)$

Subtract $8$ from $6$ .

$8 x - 2 = 2 (3 x + 4)$

Step 2

Simplify $2 (3 x + 4)$ .

Apply the distributive property.

$8 x - 2 = 2 (3 x) + 2 \cdot 4$

Multiply.

Multiply $3$ by $2$ .

$8 x - 2 = 6 x + 2 \cdot 4$

Multiply $2$ by $4$ .

$8 x - 2 = 6 x + 8$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$8 x - 2 - 6 x = 8$

Subtract $6 x$ from $8 x$ .

$2 x - 2 = 8$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Add $2$ to both sides of the equation.

$2 x = 8 + 2$

Add $8$ and $2$ .

$2 x = 10$

Step 5

Divide each term in $2 x = 10$ by $2$ and simplify.

Divide each term in $2 x = 10$ by $2$ .

$\frac{2 x}{2} = \frac{10}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{10}{2}$

Divide $x$ by $1$ .

$x = \frac{10}{2}$

Simplify the right side.

Divide $10$ by $2$ .

$x = 5$