Solve for x (6+8x)/2=5x

$\frac{6 + 8 x}{2} = 5 x$

Step 1

Cancel the common factor of $6 + 8 x$ and $2$ .

Factor $2$ out of $6$ .

$\frac{2 \cdot 3 + 8 x}{2} = 5 x$

Factor $2$ out of $8 x$ .

$\frac{2 \cdot 3 + 2 (4 x)}{2} = 5 x$

Factor $2$ out of $2 (3) + 2 (4 x)$ .

$\frac{2 (3 + 4 x)}{2} = 5 x$

Cancel the common factors.

Factor $2$ out of $2$ .

$\frac{2 (3 + 4 x)}{2 (1)} = 5 x$

Cancel the common factor.

$\frac{2 (3 + 4 x)}{2 \cdot 1} = 5 x$

Rewrite the expression.

$\frac{3 + 4 x}{1} = 5 x$

Divide $3 + 4 x$ by $1$ .

$3 + 4 x = 5 x$

Step 2

Solve for $x$ .

Move all terms containing $x$ to the left side of the equation.

Subtract $5 x$ from both sides of the equation.

$3 + 4 x - 5 x = 0$

Subtract $5 x$ from $4 x$ .

$3 - x = 0$

Subtract $3$ from both sides of the equation.

$- x = - 3$

Divide each term in $- x = - 3$ by $- 1$ and simplify.

Divide each term in $- x = - 3$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 3}{- 1}$

Simplify the left side.

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 3}{- 1}$

Divide $x$ by $1$ .

$x = \frac{- 3}{- 1}$

Simplify the right side.

Divide $- 3$ by $- 1$ .

$x = 3$