Solve for x 6(x+1)-10=4(x-1)+2x

$6 (x + 1) - 10 = 4 (x - 1) + 2 x$

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$4 (x - 1) + 2 x = 6 (x + 1) - 10$

Simplify $4 (x - 1) + 2 x$ .

Simplify each term.

Apply the distributive property.

$4 x + 4 \cdot - 1 + 2 x = 6 (x + 1) - 10$

Multiply $4$ by $- 1$ .

$4 x - 4 + 2 x = 6 (x + 1) - 10$

Add $4 x$ and $2 x$ .

$6 x - 4 = 6 (x + 1) - 10$

Simplify $6 (x + 1) - 10$ .

Simplify each term.

Apply the distributive property.

$6 x - 4 = 6 x + 6 \cdot 1 - 10$

Multiply $6$ by $1$ .

$6 x - 4 = 6 x + 6 - 10$

Subtract $10$ from $6$ .

$6 x - 4 = 6 x - 4$

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$6 x - 4 - 6 x = - 4$

Combine the opposite terms in $6 x - 4 - 6 x$ .

Subtract $6 x$ from $6 x$ .

$0 - 4 = - 4$

Subtract $4$ from $0$ .

$- 4 = - 4$

Since $- 4 = - 4$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$