Solve for x 6(x+4)=8(x-2)

$6 (x + 4) = 8 (x - 2)$

Step 1

Simplify $6 (x + 4)$ .

Rewrite.

$0 + 0 + 6 (x + 4) = 8 (x - 2)$

Simplify by adding zeros.

$6 (x + 4) = 8 (x - 2)$

Apply the distributive property.

$6 x + 6 \cdot 4 = 8 (x - 2)$

Multiply $6$ by $4$ .

$6 x + 24 = 8 (x - 2)$

Step 2

Simplify $8 (x - 2)$ .

Apply the distributive property.

$6 x + 24 = 8 x + 8 \cdot - 2$

Multiply $8$ by $- 2$ .

$6 x + 24 = 8 x - 16$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $8 x$ from both sides of the equation.

$6 x + 24 - 8 x = - 16$

Subtract $8 x$ from $6 x$ .

$- 2 x + 24 = - 16$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $24$ from both sides of the equation.

$- 2 x = - 16 - 24$

Subtract $24$ from $- 16$ .

$- 2 x = - 40$

Step 5

Divide each term in $- 2 x = - 40$ by $- 2$ and simplify.

Divide each term in $- 2 x = - 40$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 40}{- 2}$

Simplify the left side.

Cancel the common factor of $- 2$ .

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 40}{- 2}$

Divide $x$ by $1$ .

$x = \frac{- 40}{- 2}$

Simplify the right side.

Divide $- 40$ by $- 2$ .

$x = 20$