Solve for x 6(x-5)=4x+20

$6 (x - 5) = 4 x + 20$

Step 1

Simplify $6 (x - 5)$ .

Rewrite.

$0 + 0 + 6 (x - 5) = 4 x + 20$

Simplify by adding zeros.

$6 (x - 5) = 4 x + 20$

Apply the distributive property.

$6 x + 6 \cdot - 5 = 4 x + 20$

Multiply $6$ by $- 5$ .

$6 x - 30 = 4 x + 20$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$6 x - 30 - 4 x = 20$

Subtract $4 x$ from $6 x$ .

$2 x - 30 = 20$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Add $30$ to both sides of the equation.

$2 x = 20 + 30$

Add $20$ and $30$ .

$2 x = 50$

Step 4

Divide each term in $2 x = 50$ by $2$ and simplify.

Divide each term in $2 x = 50$ by $2$ .

$\frac{2 x}{2} = \frac{50}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{50}{2}$

Divide $x$ by $1$ .

$x = \frac{50}{2}$

Simplify the right side.

Divide $50$ by $2$ .

$x = 25$