Solve for x 68=1/5(20x+50)+2

$68 = \frac{1}{5} (20 x + 50) + 2$

Rewrite the equation as $\frac{1}{5} \cdot (20 x + 50) + 2 = 68$ .

$\frac{1}{5} \cdot (20 x + 50) + 2 = 68$

Simplify $\frac{1}{5} \cdot (20 x + 50) + 2$ .

Simplify each term.

Apply the distributive property.

$\frac{1}{5} (20 x) + \frac{1}{5} \cdot 50 + 2 = 68$

Cancel the common factor of $5$ .

Factor $5$ out of $20 x$ .

$\frac{1}{5} (5 (4 x)) + \frac{1}{5} \cdot 50 + 2 = 68$

Cancel the common factor.

$\frac{1}{5} (5 (4 x)) + \frac{1}{5} \cdot 50 + 2 = 68$

Rewrite the expression.

$4 x + \frac{1}{5} \cdot 50 + 2 = 68$

Cancel the common factor of $5$ .

Factor $5$ out of $50$ .

$4 x + \frac{1}{5} \cdot (5 (10)) + 2 = 68$

Cancel the common factor.

$4 x + \frac{1}{5} \cdot (5 \cdot 10) + 2 = 68$

Rewrite the expression.

$4 x + 10 + 2 = 68$

Add $10$ and $2$ .

$4 x + 12 = 68$

Move all terms not containing $x$ to the right side of the equation.

Subtract $12$ from both sides of the equation.

$4 x = 68 - 12$

Subtract $12$ from $68$ .

$4 x = 56$

Divide each term in $4 x = 56$ by $4$ and simplify.

Divide each term in $4 x = 56$ by $4$ .

$\frac{4 x}{4} = \frac{56}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{56}{4}$

Divide $x$ by $1$ .

$x = \frac{56}{4}$

Simplify the right side.

Divide $56$ by $4$ .

$x = 14$