Solve for x 6x^2+1<=0

$6 x^{2} + 1 \leq 0$

Step 1

Subtract $1$ from both sides of the inequality.

$6 x^{2} \leq - 1$

Step 2

Divide each term in $6 x^{2} \leq - 1$ by $6$ and simplify.

Divide each term in $6 x^{2} \leq - 1$ by $6$ .

$\frac{6 x^{2}}{6} \leq \frac{- 1}{6}$

Simplify the left side.

Cancel the common factor of $6$ .

Cancel the common factor.

$\frac{6 x^{2}}{6} \leq \frac{- 1}{6}$

Divide $x^{2}$ by $1$ .

$x^{2} \leq \frac{- 1}{6}$

Simplify the right side.

Move the negative in front of the fraction.

$x^{2} \leq - \frac{1}{6}$

Step 3

Since the left side has an even power, it is always positive for all real numbers.

No solution