Solve for x -6x+2(5(x+1)+8)=38

$- 6 x + 2 (5 (x + 1) + 8) = 38$

Step 1

Simplify $- 6 x + 2 (5 (x + 1) + 8)$ .

Simplify each term.

Apply the distributive property.

$- 6 x + 2 (5 x + 5 \cdot 1 + 8) = 38$

Multiply $5$ by $1$ .

$- 6 x + 2 (5 x + 5 + 8) = 38$

Add $5$ and $8$ .

$- 6 x + 2 (5 x + 13) = 38$

Apply the distributive property.

$- 6 x + 2 (5 x) + 2 \cdot 13 = 38$

Multiply $5$ by $2$ .

$- 6 x + 10 x + 2 \cdot 13 = 38$

Multiply $2$ by $13$ .

$- 6 x + 10 x + 26 = 38$

Add $- 6 x$ and $10 x$ .

$4 x + 26 = 38$

Step 2

Move all terms not containing $x$ to the right side of the equation.

Subtract $26$ from both sides of the equation.

$4 x = 38 - 26$

Subtract $26$ from $38$ .

$4 x = 12$

Step 3

Divide each term in $4 x = 12$ by $4$ and simplify.

Divide each term in $4 x = 12$ by $4$ .

$\frac{4 x}{4} = \frac{12}{4}$

Simplify the left side.

Cancel the common factor of $4$ .

Cancel the common factor.

$\frac{4 x}{4} = \frac{12}{4}$

Divide $x$ by $1$ .

$x = \frac{12}{4}$

Simplify the right side.

Divide $12$ by $4$ .

$x = 3$