Solve for x 6x-(2x-1)=9x+2(2-x)

$6 x - (2 x - 1) = 9 x + 2 (2 - x)$

Simplify $6 x - (2 x - 1)$ .

Simplify each term.

Apply the distributive property.

$6 x - (2 x) - - 1 = 9 x + 2 (2 - x)$

Multiply $2$ by $- 1$ .

$6 x - 2 x - - 1 = 9 x + 2 (2 - x)$

Multiply $- 1$ by $- 1$ .

$6 x - 2 x + 1 = 9 x + 2 (2 - x)$

Subtract $2 x$ from $6 x$ .

$4 x + 1 = 9 x + 2 (2 - x)$

Simplify $9 x + 2 (2 - x)$ .

Simplify each term.

Apply the distributive property.

$4 x + 1 = 9 x + 2 \cdot 2 + 2 (- x)$

Multiply $2$ by $2$ .

$4 x + 1 = 9 x + 4 + 2 (- x)$

Multiply $- 1$ by $2$ .

$4 x + 1 = 9 x + 4 - 2 x$

Subtract $2 x$ from $9 x$ .

$4 x + 1 = 7 x + 4$

Move all terms containing $x$ to the left side of the equation.

Subtract $7 x$ from both sides of the equation.

$4 x + 1 - 7 x = 4$

Subtract $7 x$ from $4 x$ .

$- 3 x + 1 = 4$

Move all terms not containing $x$ to the right side of the equation.

Subtract $1$ from both sides of the equation.

$- 3 x = 4 - 1$

Subtract $1$ from $4$ .

$- 3 x = 3$

Divide each term in $- 3 x = 3$ by $- 3$ and simplify.

Divide each term in $- 3 x = 3$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{3}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{3}{- 3}$

Divide $x$ by $1$ .

$x = \frac{3}{- 3}$

Simplify the right side.

Divide $3$ by $- 3$ .

$x = - 1$