Solve for x 6x-(2x+3)>4x-5

$6 x - (2 x + 3) > 4 x - 5$

Simplify $6 x - (2 x + 3)$ .

Simplify each term.

Apply the distributive property.

$6 x - (2 x) - 1 \cdot 3 > 4 x - 5$

Multiply $2$ by $- 1$ .

$6 x - 2 x - 1 \cdot 3 > 4 x - 5$

Multiply $- 1$ by $3$ .

$6 x - 2 x - 3 > 4 x - 5$

Subtract $2 x$ from $6 x$ .

$4 x - 3 > 4 x - 5$

Move all terms containing $x$ to the left side of the inequality.

Subtract $4 x$ from both sides of the inequality.

$4 x - 3 - 4 x > - 5$

Combine the opposite terms in $4 x - 3 - 4 x$ .

Subtract $4 x$ from $4 x$ .

$0 - 3 > - 5$

Subtract $3$ from $0$ .

$- 3 > - 5$

Since $- 3 > - 5$ , the inequality will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$