Solve for x 6x+3-6x=3

$6 x + 3 - 6 x = 3$

Combine the opposite terms in $6 x + 3 - 6 x$ .

Subtract $6 x$ from $6 x$ .

$0 + 3 = 3$

Add $0$ and $3$ .

$3 = 3$

Since $3 = 3$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$