Solve for x -(6x-(4x+8))=9+(6x+3)

$- (6 x - (4 x + 8)) = 9 + (6 x + 3)$

Step 1

Simplify $- (6 x - (4 x + 8))$ .

Rewrite.

$0 + 0 - (6 x - (4 x + 8)) = 9 + 6 x + 3$

Simplify by adding zeros.

$- (6 x - (4 x + 8)) = 9 + 6 x + 3$

Simplify each term.

Apply the distributive property.

$- (6 x - (4 x) - 1 \cdot 8) = 9 + 6 x + 3$

Multiply $4$ by $- 1$ .

$- (6 x - 4 x - 1 \cdot 8) = 9 + 6 x + 3$

Multiply $- 1$ by $8$ .

$- (6 x - 4 x - 8) = 9 + 6 x + 3$

Simplify terms.

Subtract $4 x$ from $6 x$ .

$- (2 x - 8) = 9 + 6 x + 3$

Apply the distributive property.

$- (2 x) - - 8 = 9 + 6 x + 3$

Multiply.

Multiply $2$ by $- 1$ .

$- 2 x - - 8 = 9 + 6 x + 3$

Multiply $- 1$ by $- 8$ .

$- 2 x + 8 = 9 + 6 x + 3$

Step 2

Add $9$ and $3$ .

$- 2 x + 8 = 6 x + 12$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$- 2 x + 8 - 6 x = 12$

Subtract $6 x$ from $- 2 x$ .

$- 8 x + 8 = 12$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $8$ from both sides of the equation.

$- 8 x = 12 - 8$

Subtract $8$ from $12$ .

$- 8 x = 4$

Step 5

Divide each term in $- 8 x = 4$ by $- 8$ and simplify.

Divide each term in $- 8 x = 4$ by $- 8$ .

$\frac{- 8 x}{- 8} = \frac{4}{- 8}$

Simplify the left side.

Cancel the common factor of $- 8$ .

Cancel the common factor.

$\frac{- 8 x}{- 8} = \frac{4}{- 8}$

Divide $x$ by $1$ .

$x = \frac{4}{- 8}$

Simplify the right side.

Cancel the common factor of $4$ and $- 8$ .

Factor $4$ out of $4$ .

$x = \frac{4 (1)}{- 8}$

Cancel the common factors.

Factor $4$ out of $- 8$ .

$x = \frac{4 \cdot 1}{4 \cdot - 2}$

Cancel the common factor.

$x = \frac{4 \cdot 1}{4 \cdot - 2}$

Rewrite the expression.

$x = \frac{1}{- 2}$

Move the negative in front of the fraction.

$x = - \frac{1}{2}$

Step 6

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{1}{2}$

Decimal Form:

$x = - 0.5$

Solve for x -(6x-(4x+8))=9+(6x+3)

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