Solve for x 6x+5-2x=4+4x+1

$6 x + 5 - 2 x = 4 + 4 x + 1$

Subtract $2 x$ from $6 x$ .

$4 x + 5 = 4 + 4 x + 1$

Add $4$ and $1$ .

$4 x + 5 = 4 x + 5$

Move all terms containing $x$ to the left side of the equation.

Subtract $4 x$ from both sides of the equation.

$4 x + 5 - 4 x = 5$

Combine the opposite terms in $4 x + 5 - 4 x$ .

Subtract $4 x$ from $4 x$ .

$0 + 5 = 5$

Add $0$ and $5$ .

$5 = 5$

Since $5 = 5$ , the equation will always be true for any value of $x$ .

All real numbers

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$