Solve for x 7^(2x)=7^(x-3)

$7^{2 x} = 7^{x - 3}$

Create equivalent expressions in the equation that all have equal bases.

$7^{2 x} = 7^{x - 3}$

Since the bases are the same, then two expressions are only equal if the exponents are also equal.

$2 x = x - 3$

Move all terms containing $x$ to the left side of the equation.

Subtract $x$ from both sides of the equation.

$2 x - x = - 3$

Subtract $x$ from $2 x$ .

$x = - 3$