Solve for x 7=3(5+x)

$7 = 3 (5 + x)$

Rewrite the equation as $3 (5 + x) = 7$ .

$3 (5 + x) = 7$

Divide each term in $3 (5 + x) = 7$ by $3$ and simplify.

Divide each term in $3 (5 + x) = 7$ by $3$ .

$\frac{3 (5 + x)}{3} = \frac{7}{3}$

Simplify the left side.

Cancel the common factor of $3$ .

Cancel the common factor.

$\frac{3 (5 + x)}{3} = \frac{7}{3}$

Divide $5 + x$ by $1$ .

$5 + x = \frac{7}{3}$

Move all terms not containing $x$ to the right side of the equation.

Subtract $5$ from both sides of the equation.

$x = \frac{7}{3} - 5$

To write $- 5$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$x = \frac{7}{3} - 5 \cdot \frac{3}{3}$

Combine $- 5$ and $\frac{3}{3}$ .

$x = \frac{7}{3} + \frac{- 5 \cdot 3}{3}$

Combine the numerators over the common denominator.

$x = \frac{7 - 5 \cdot 3}{3}$

Simplify the numerator.

Multiply $- 5$ by $3$ .

$x = \frac{7 - 15}{3}$

Subtract $15$ from $7$ .

$x = \frac{- 8}{3}$

Move the negative in front of the fraction.

$x = - \frac{8}{3}$

The result can be shown in multiple forms.

Exact Form:

$x = - \frac{8}{3}$

Decimal Form:

$x = - 2.\overline{6}$

Mixed Number Form:

$x = - 2 \frac{2}{3}$