Solve for x 7+3x-12x=3x+1

$7 + 3 x - 12 x = 3 x + 1$

Step 1

Subtract $12 x$ from $3 x$ .

$7 - 9 x = 3 x + 1$

Step 2

Move all terms containing $x$ to the left side of the equation.

Subtract $3 x$ from both sides of the equation.

$7 - 9 x - 3 x = 1$

Subtract $3 x$ from $- 9 x$ .

$7 - 12 x = 1$

Step 3

Move all terms not containing $x$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$- 12 x = 1 - 7$

Subtract $7$ from $1$ .

$- 12 x = - 6$

Step 4

Divide each term in $- 12 x = - 6$ by $- 12$ and simplify.

Divide each term in $- 12 x = - 6$ by $- 12$ .

$\frac{- 12 x}{- 12} = \frac{- 6}{- 12}$

Simplify the left side.

Cancel the common factor of $- 12$ .

Cancel the common factor.

$\frac{- 12 x}{- 12} = \frac{- 6}{- 12}$

Divide $x$ by $1$ .

$x = \frac{- 6}{- 12}$

Simplify the right side.

Cancel the common factor of $- 6$ and $- 12$ .

Factor $- 6$ out of $- 6$ .

$x = \frac{- 6 (1)}{- 12}$

Cancel the common factors.

Factor $- 6$ out of $- 12$ .

$x = \frac{- 6 \cdot 1}{- 6 \cdot 2}$

Cancel the common factor.

$x = \frac{- 6 \cdot 1}{- 6 \cdot 2}$

Rewrite the expression.

$x = \frac{1}{2}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$x = \frac{1}{2}$

Decimal Form:

$x = 0.5$