Solve for x (-7(3x+6))/3=7

$\frac{- 7 (3 x + 6)}{3} = 7$

Cancel the common factor of $3 x + 6$ and $3$ .

Factor $3$ out of $- 7 (3 x + 6)$ .

$\frac{3 (- 7 (x + 2))}{3} = 7$

Cancel the common factors.

Factor $3$ out of $3$ .

$\frac{3 (- 7 (x + 2))}{3 (1)} = 7$

Cancel the common factor.

$\frac{3 (- 7 (x + 2))}{3 \cdot 1} = 7$

Rewrite the expression.

$\frac{- 7 (x + 2)}{1} = 7$

Divide $- 7 (x + 2)$ by $1$ .

$- 7 (x + 2) = 7$

Solve for $x$ .

Divide each term in $- 7 (x + 2) = 7$ by $- 7$ and simplify.

Divide each term in $- 7 (x + 2) = 7$ by $- 7$ .

$\frac{- 7 (x + 2)}{- 7} = \frac{7}{- 7}$

Simplify the left side.

Cancel the common factor of $- 7$ .

Cancel the common factor.

$\frac{- 7 (x + 2)}{- 7} = \frac{7}{- 7}$

Divide $x + 2$ by $1$ .

$x + 2 = \frac{7}{- 7}$

Simplify the right side.

Divide $7$ by $- 7$ .

$x + 2 = - 1$

Move all terms not containing $x$ to the right side of the equation.

Subtract $2$ from both sides of the equation.

$x = - 1 - 2$

Subtract $2$ from $- 1$ .

$x = - 3$