Solve for x -7+((4x+2)/2)=8

$- 7 + (\frac{4 x + 2}{2}) = 8$

Simplify $- 7 + \frac{4 x + 2}{2}$ .

Cancel the common factor of $4 x + 2$ and $2$ .

Factor $2$ out of $4 x$ .

$- 7 + \frac{2 (2 x) + 2}{2} = 8$

Factor $2$ out of $2$ .

$- 7 + \frac{2 (2 x) + 2 \cdot 1}{2} = 8$

Factor $2$ out of $2 (2 x) + 2 (1)$ .

$- 7 + \frac{2 (2 x + 1)}{2} = 8$

Cancel the common factors.

Factor $2$ out of $2$ .

$- 7 + \frac{2 (2 x + 1)}{2 (1)} = 8$

Cancel the common factor.

$- 7 + \frac{2 (2 x + 1)}{2 \cdot 1} = 8$

Rewrite the expression.

$- 7 + \frac{2 x + 1}{1} = 8$

Divide $2 x + 1$ by $1$ .

$- 7 + 2 x + 1 = 8$

Add $- 7$ and $1$ .

$2 x - 6 = 8$

Move all terms not containing $x$ to the right side of the equation.

Add $6$ to both sides of the equation.

$2 x = 8 + 6$

Add $8$ and $6$ .

$2 x = 14$

Divide each term in $2 x = 14$ by $2$ and simplify.

Divide each term in $2 x = 14$ by $2$ .

$\frac{2 x}{2} = \frac{14}{2}$

Simplify the left side.

Cancel the common factor of $2$ .

Cancel the common factor.

$\frac{2 x}{2} = \frac{14}{2}$

Divide $x$ by $1$ .

$x = \frac{14}{2}$

Simplify the right side.

Divide $14$ by $2$ .

$x = 7$