Solve for x 7(x+2)^(1/3)=0

$7 {(x + 2)}^{\frac{1}{3}} = 0$

Step 1

Divide each term in $7 {(x + 2)}^{\frac{1}{3}} = 0$ by $7$ and simplify.

Divide each term in $7 {(x + 2)}^{\frac{1}{3}} = 0$ by $7$ .

$\frac{7 {(x + 2)}^{\frac{1}{3}}}{7} = \frac{0}{7}$

Simplify the left side.

Cancel the common factor.

$\frac{7 {(x + 2)}^{\frac{1}{3}}}{7} = \frac{0}{7}$

Divide ${(x + 2)}^{\frac{1}{3}}$ by $1$ .

${(x + 2)}^{\frac{1}{3}} = \frac{0}{7}$

Simplify the right side.

Divide $0$ by $7$ .

${(x + 2)}^{\frac{1}{3}} = 0$

Step 2

Set the $x + 2$ equal to $0$ .

$x + 2 = 0$

Step 3

Subtract $2$ from both sides of the equation.

$x = - 2$