Solve for x 7(x+2)=6(x+5)

$7 (x + 2) = 6 (x + 5)$

Step 1

Simplify $7 (x + 2)$ .

Rewrite.

$0 + 0 + 7 (x + 2) = 6 (x + 5)$

Simplify by adding zeros.

$7 (x + 2) = 6 (x + 5)$

Apply the distributive property.

$7 x + 7 \cdot 2 = 6 (x + 5)$

Multiply $7$ by $2$ .

$7 x + 14 = 6 (x + 5)$

Step 2

Simplify $6 (x + 5)$ .

Apply the distributive property.

$7 x + 14 = 6 x + 6 \cdot 5$

Multiply $6$ by $5$ .

$7 x + 14 = 6 x + 30$

Step 3

Move all terms containing $x$ to the left side of the equation.

Subtract $6 x$ from both sides of the equation.

$7 x + 14 - 6 x = 30$

Subtract $6 x$ from $7 x$ .

$x + 14 = 30$

Step 4

Move all terms not containing $x$ to the right side of the equation.

Subtract $14$ from both sides of the equation.

$x = 30 - 14$

Subtract $14$ from $30$ .

$x = 16$