Solve for x 7(x+3)-3(x-2)=16(2x-3)+19

$7 (x + 3) - 3 (x - 2) = 16 (2 x - 3) + 19$

Simplify $7 (x + 3) - 3 (x - 2)$ .

Simplify each term.

Apply the distributive property.

$7 x + 7 \cdot 3 - 3 (x - 2) = 16 (2 x - 3) + 19$

Multiply $7$ by $3$ .

$7 x + 21 - 3 (x - 2) = 16 (2 x - 3) + 19$

Apply the distributive property.

$7 x + 21 - 3 x - 3 \cdot - 2 = 16 (2 x - 3) + 19$

Multiply $- 3$ by $- 2$ .

$7 x + 21 - 3 x + 6 = 16 (2 x - 3) + 19$

Simplify by adding terms.

Subtract $3 x$ from $7 x$ .

$4 x + 21 + 6 = 16 (2 x - 3) + 19$

Add $21$ and $6$ .

$4 x + 27 = 16 (2 x - 3) + 19$

Simplify $16 (2 x - 3) + 19$ .

Simplify each term.

Apply the distributive property.

$4 x + 27 = 16 (2 x) + 16 \cdot - 3 + 19$

Multiply $2$ by $16$ .

$4 x + 27 = 32 x + 16 \cdot - 3 + 19$

Multiply $16$ by $- 3$ .

$4 x + 27 = 32 x - 48 + 19$

Add $- 48$ and $19$ .

$4 x + 27 = 32 x - 29$

Move all terms containing $x$ to the left side of the equation.

Subtract $32 x$ from both sides of the equation.

$4 x + 27 - 32 x = - 29$

Subtract $32 x$ from $4 x$ .

$- 28 x + 27 = - 29$

Move all terms not containing $x$ to the right side of the equation.

Subtract $27$ from both sides of the equation.

$- 28 x = - 29 - 27$

Subtract $27$ from $- 29$ .

$- 28 x = - 56$

Divide each term in $- 28 x = - 56$ by $- 28$ and simplify.

Divide each term in $- 28 x = - 56$ by $- 28$ .

$\frac{- 28 x}{- 28} = \frac{- 56}{- 28}$

Simplify the left side.

Cancel the common factor of $- 28$ .

Cancel the common factor.

$\frac{- 28 x}{- 28} = \frac{- 56}{- 28}$

Divide $x$ by $1$ .

$x = \frac{- 56}{- 28}$

Simplify the right side.

Divide $- 56$ by $- 28$ .

$x = 2$

Solve for x 7(x+3)-3(x-2)=16(2x-3)+19

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