Solve for x 7-x+3=9x+10

$7 - x + 3 = 9 x + 10$

Add $7$ and $3$ .

$- x + 10 = 9 x + 10$

Move all terms containing $x$ to the left side of the equation.

Subtract $9 x$ from both sides of the equation.

$- x + 10 - 9 x = 10$

Subtract $9 x$ from $- x$ .

$- 10 x + 10 = 10$

Move all terms not containing $x$ to the right side of the equation.

Subtract $10$ from both sides of the equation.

$- 10 x = 10 - 10$

Subtract $10$ from $10$ .

$- 10 x = 0$

Divide each term in $- 10 x = 0$ by $- 10$ and simplify.

Divide each term in $- 10 x = 0$ by $- 10$ .

$\frac{- 10 x}{- 10} = \frac{0}{- 10}$

Simplify the left side.

Cancel the common factor of $- 10$ .

Cancel the common factor.

$\frac{- 10 x}{- 10} = \frac{0}{- 10}$

Divide $x$ by $1$ .

$x = \frac{0}{- 10}$

Simplify the right side.

Divide $0$ by $- 10$ .

$x = 0$