Solve for x 7(x+4)=3x+12+x-5

$7 (x + 4) = 3 x + 12 + x - 5$

Step 1

Since $x$ is on the right side of the equation, switch the sides so it is on the left side of the equation.

$3 x + 12 + x - 5 = 7 (x + 4)$

Step 2

Simplify $3 x + 12 + x - 5$ .

Add $3 x$ and $x$ .

$4 x + 12 - 5 = 7 (x + 4)$

Subtract $5$ from $12$ .

$4 x + 7 = 7 (x + 4)$

Step 3

Simplify $7 (x + 4)$ .

Apply the distributive property.

$4 x + 7 = 7 x + 7 \cdot 4$

Multiply $7$ by $4$ .

$4 x + 7 = 7 x + 28$

Step 4

Move all terms containing $x$ to the left side of the equation.

Subtract $7 x$ from both sides of the equation.

$4 x + 7 - 7 x = 28$

Subtract $7 x$ from $4 x$ .

$- 3 x + 7 = 28$

Step 5

Move all terms not containing $x$ to the right side of the equation.

Subtract $7$ from both sides of the equation.

$- 3 x = 28 - 7$

Subtract $7$ from $28$ .

$- 3 x = 21$

Step 6

Divide each term in $- 3 x = 21$ by $- 3$ and simplify.

Divide each term in $- 3 x = 21$ by $- 3$ .

$\frac{- 3 x}{- 3} = \frac{21}{- 3}$

Simplify the left side.

Cancel the common factor of $- 3$ .

Cancel the common factor.

$\frac{- 3 x}{- 3} = \frac{21}{- 3}$

Divide $x$ by $1$ .

$x = \frac{21}{- 3}$

Simplify the right side.

Divide $21$ by $- 3$ .

$x = - 7$