Solve for x -79=7x+3(4x-1)

$- 79 = 7 x + 3 (4 x - 1)$

Rewrite the equation as $7 x + 3 (4 x - 1) = - 79$ .

$7 x + 3 (4 x - 1) = - 79$

Simplify $7 x + 3 (4 x - 1)$ .

Simplify each term.

Apply the distributive property.

$7 x + 3 (4 x) + 3 \cdot - 1 = - 79$

Multiply $4$ by $3$ .

$7 x + 12 x + 3 \cdot - 1 = - 79$

Multiply $3$ by $- 1$ .

$7 x + 12 x - 3 = - 79$

Add $7 x$ and $12 x$ .

$19 x - 3 = - 79$

Move all terms not containing $x$ to the right side of the equation.

Add $3$ to both sides of the equation.

$19 x = - 79 + 3$

Add $- 79$ and $3$ .

$19 x = - 76$

Divide each term in $19 x = - 76$ by $19$ and simplify.

Divide each term in $19 x = - 76$ by $19$ .

$\frac{19 x}{19} = \frac{- 76}{19}$

Simplify the left side.

Cancel the common factor of $19$ .

Cancel the common factor.

$\frac{19 x}{19} = \frac{- 76}{19}$

Divide $x$ by $1$ .

$x = \frac{- 76}{19}$

Simplify the right side.

Divide $- 76$ by $19$ .

$x = - 4$