Solve for x 7x-(3x+5)-8=1/2(8x+20)-7x+5

$7 x - (3 x + 5) - 8 = \frac{1}{2} (8 x + 20) - 7 x + 5$

Simplify $7 x - (3 x + 5) - 8$ .

Simplify each term.

Apply the distributive property.

$7 x - (3 x) - 1 \cdot 5 - 8 = \frac{1}{2} \cdot (8 x + 20) - 7 x + 5$

Multiply $3$ by $- 1$ .

$7 x - 3 x - 1 \cdot 5 - 8 = \frac{1}{2} \cdot (8 x + 20) - 7 x + 5$

Multiply $- 1$ by $5$ .

$7 x - 3 x - 5 - 8 = \frac{1}{2} \cdot (8 x + 20) - 7 x + 5$

Simplify by adding terms.

Subtract $3 x$ from $7 x$ .

$4 x - 5 - 8 = \frac{1}{2} \cdot (8 x + 20) - 7 x + 5$

Subtract $8$ from $- 5$ .

$4 x - 13 = \frac{1}{2} \cdot (8 x + 20) - 7 x + 5$

Simplify $\frac{1}{2} \cdot (8 x + 20) - 7 x + 5$ .

Simplify each term.

Apply the distributive property.

$4 x - 13 = \frac{1}{2} (8 x) + \frac{1}{2} \cdot 20 - 7 x + 5$

Cancel the common factor of $2$ .

Factor $2$ out of $8 x$ .

$4 x - 13 = \frac{1}{2} (2 (4 x)) + \frac{1}{2} \cdot 20 - 7 x + 5$

Cancel the common factor.

$4 x - 13 = \frac{1}{2} (2 (4 x)) + \frac{1}{2} \cdot 20 - 7 x + 5$

Rewrite the expression.

$4 x - 13 = 4 x + \frac{1}{2} \cdot 20 - 7 x + 5$

Cancel the common factor of $2$ .

Factor $2$ out of $20$ .

$4 x - 13 = 4 x + \frac{1}{2} \cdot (2 (10)) - 7 x + 5$

Cancel the common factor.

$4 x - 13 = 4 x + \frac{1}{2} \cdot (2 \cdot 10) - 7 x + 5$

Rewrite the expression.

$4 x - 13 = 4 x + 10 - 7 x + 5$

Simplify by adding terms.

Subtract $7 x$ from $4 x$ .

$4 x - 13 = - 3 x + 10 + 5$

Add $10$ and $5$ .

$4 x - 13 = - 3 x + 15$

Move all terms containing $x$ to the left side of the equation.

Add $3 x$ to both sides of the equation.

$4 x - 13 + 3 x = 15$

Add $4 x$ and $3 x$ .

$7 x - 13 = 15$

Move all terms not containing $x$ to the right side of the equation.

Add $13$ to both sides of the equation.

$7 x = 15 + 13$

Add $15$ and $13$ .

$7 x = 28$

Divide each term in $7 x = 28$ by $7$ and simplify.

Divide each term in $7 x = 28$ by $7$ .

$\frac{7 x}{7} = \frac{28}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{28}{7}$

Divide $x$ by $1$ .

$x = \frac{28}{7}$

Simplify the right side.

Divide $28$ by $7$ .

$x = 4$

Solve for x 7x-(3x+5)-8=1/2(8x+20)-7x+5

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