Solve for x 7x+3y+12=0

$7 x + 3 y + 12 = 0$

Step 1

Move all terms not containing $x$ to the right side of the equation.

Subtract $3 y$ from both sides of the equation.

$7 x + 12 = - 3 y$

Subtract $12$ from both sides of the equation.

$7 x = - 3 y - 12$

Step 2

Divide each term in $7 x = - 3 y - 12$ by $7$ and simplify.

Divide each term in $7 x = - 3 y - 12$ by $7$ .

$\frac{7 x}{7} = \frac{- 3 y}{7} + \frac{- 12}{7}$

Simplify the left side.

Cancel the common factor of $7$ .

Cancel the common factor.

$\frac{7 x}{7} = \frac{- 3 y}{7} + \frac{- 12}{7}$

Divide $x$ by $1$ .

$x = \frac{- 3 y}{7} + \frac{- 12}{7}$

Simplify the right side.

Simplify each term.

Move the negative in front of the fraction.

$x = - \frac{(3) y}{7} + \frac{- 12}{7}$

Move the negative in front of the fraction.

$x = - \frac{3 y}{7} - \frac{12}{7}$